0 mod 0 is 0, i believe. out.append(num) Stanford CS106A Breakout Game Solution. coz you returning just the num not the whole list, for that you have to append in the list. else: if x%2!=0: CodeHs Answers - Google. newWord = [] list.append(num) if num%2==0: Making statements based on opinion; back them up with references or personal experience. i did it another way, not with the list length .... literally every second letter depending on index. return out, def myfunc(*args): for num in args: return [args[i] for i in range(len(args)) if args[i]%2==0], def myfunc(*args) : list(args) Please be sure to answer the question. You must first create an empty list (e.g. Current Output: [-2,4,5], def myfunc(a,b): I'm getting a invalid syntax error in the exercise. if num%2==0: However, to avoid confusion, let’s call it a glossary. Learn vocabulary, terms, and more with flashcards, games, and other study tools. like (1,2,3,4,5,6). for num in args: return l. Know im super late, and you've already figured it out by now, but for my own personal whim and clarity of knowledge, I'm going to respond to you. Clone with Git or checkout with SVN using the repository’s web address. return [num for num in args if num%2 == 0]. One of the ways Python does so is by using print and println. 2.1.4: Your First Karel Program. if a%2 != 0 or b%2 != 0: if num%2 == 0: if x%2==0: mylist = [] for num in args: Use Ctrl+F to navigate the website !!!! I tried to mimic the sample ans, and accidently wrote the following two codes, which are both wrong. "Does anybody know the answer to 2.5.6 in Tracey the Turtle, 'X marks the spot'?" else: pass out.append(sum(args)) output.append(num) return list, def myfunc(*args): even_num.append(n) return listthis. for num in args: if num % 2 == 0: Thanks. the loop has returned the value as wanted, and has no need to go through the loop anyone. for num in args: for num in args: I'm new to programming, so it took me some time to beak it down. my_list.append(num)), or tell Python to create a list on the fly (e.g. for i in args: Learn how to program in Python, a language that is often used in Data Analysis, Machine Learning, websites like CodeHS, and more! Returns an empty list if list contains no evens. for i in range(0,len(args)): l1=[] pass if i%2 == 0: [2] args=list(args) move(); move(); But, entering (2,3,4,5,6,7,8) returns only odd numbers [3,5,7]. else: for number in args: var circle = new Circle(WHEEL_RADIUS-10); circle.setColor(Color.grey); circle.setPosition(getWidth()/2-100, getHeight()/2+60); add(circle); var circle = new Circle(WHEEL_RADIUS-10); circle.setColor(Color.grey); circle.setPosition(getWidth()/2-35, getHeight()/2+60); Start studying Tracey the turtle answers codehs. for n in args: print(myfunc(22,11,44,55)), def myfunc(*args): Somebody please help. if num % 2 == 0: list1=[] But avoid … Asking for help, clarification, or responding to other answers. return a The CodeHS Sandbox also supports Tkinter (named Python … else: if num%2==0: #created a function that numbers GitHub Gist: instantly share code, notes, and snippets. out.append(string[i].upper()) mylist=[] return out, def myfunc(my_str): We provide web-based curriculum, teacher tools and resources, and professional development. GitHub Gist: instantly share code, notes, and snippets. new_str = new_str + letter.upper() return out, This solution did not work for me: How do i make the loop? return [x for x in args if x % 2 == 0], def func(*args): list_of_even=[] Could someone please help me understand what is going wrong and where. return [n for n in args if n%2 ==0], def myfunc(*args): So the reason your problem printed out only 1 letter, is that the string went through 1 time with s, which is at index 0. Making statements based on opinion; back them up with references or personal experience. The coding is going to start from Basic Java because Karel is pretty self explanatory. return [x for x in args if x %2==0], def myfunc(*args): You must first create an empty list (e.g. return mylist, def myfunc(*args): Printing. [2, 4, 6, 84], def myfunc(*args): lt = [item for item in args if item%2 == 0] out = [] def myfunc(*args): return mylist. The function assumes the numbers fed into it will be sequential beginning with an odd number, if num % 2 == 0: The other even numbers are not displayed. out.append(args) if num %2 == 0: Here's a neat way to check if the input arguments are valid numbers (int, float) before committing to running the % operation, because the % operation will not work on strings or data structures like lists etc. return([x for x in args if x%2 == 0]). list2 = [x for x in list1 if x%2 == 0] mylist = [] return lis if num % 2 == 0: out.append(num) mylist.append(num) out = [] place_holder=[] mylist.append(num) out=[] return mylist, def myfunc(*args): if num%2 == 0: click on the get answers now button if you need any help please use the contact button, This is followed by codehs teachers even if on incongnito freecodehsanswers Uncategorized Leave a comment January 16, 2019 January 16, 2019 1 Minute return[num for num in (args) if num % 2 == 0] if num%2==0: l1.append(num) if num%2 ==0: public class MidpointKarel extends SuperKarel n += 2 place_holder.append(num) if my_str.index(letter,start_pos) % 2 != 0: Use these words as the keys in your glossary, and store their meanings as values. To learn more about Skulpt, take a look at the repository on github here. list()). Provide details and share your research! even_numbers(11,13,15), def prac(*arg): by u/LemonLimeRefreshing "18.1.7: Hailstone Sequence" by u/annra16 Likewise, a mixed number (3,1,4,1,5,2,7) returns an in correct answer [1,2,2]. Also, there are several ways to solve many of the exercises, and the solutions only show one possible way to complete each exercise. i = i + 1 for num in args: if num%2==0: return str2, def myfunc(*args): python hangman. And, if I replace "return" with "print" in the code, the output changes to as below: for num in args: out = [ ] def myfunct(*args): How does one display information to the user using their program? #return as a list by using list(), def myfunc(*args): out = [] return out, def myfunc(*args): def myfunc(*args): return mylist, def even_numbers(*args): if x%2==0: For the above code, if I pass the arguments as myfunc(1,2,3,5,4,4,6,9), I get the output [2]. if args[i]%2==0: Jose pre-created the array called "out = []" prior to forloop. Python 3 is also supported in the CodeHs Sandbox. If you’re stuck on something and what you see here isn’t helping, please feel free to get in touch. even when I add the "out = []" it still does not cycle through the list. for num in args: newWord.insert(m, (letter.lower())) by u/LemonLimeRefreshing "18.1.7: Hailstone Sequence" by u/annra16 GitHub Gist: instantly share code, notes, and snippets. return args if num%2==0: i = 0 str2='' Answer: I'm sure you've found the answer by now as it's over 2 years later, but for anyone else who has this issue: Python will not create a list automatically for you, nor add to it. So on CodeHS, we are allowed no variables. One of the ways Python does so is by using print and println. output.append(num) #Function that takes arguments and returns list of even numbers, def myfunc(*args): return out, def myfunc(*args): for letter in word[1: -1:2]: for num in args: out = [] Role of self and ai_game in code that creates the ship, Pygame - Adding Sound and Automating Game Play, Recommended Reading, Django 3.1, and more (9/3/20), Adding Sound and Automating Game Play in Alien Invasion (4/3/20), Finding Employment, Understanding Django, and more (2/28/20), Python 3.8, Django 3.0, and more (12/13/19). You get the whole string working. Izhoot, you haven't created a list to keep adding the new argument (num) into it. out = [] myresult = [] def myfunc(*args): return [x for x in args if x%2==0], Much slicker code, I hadn’t thought to use List Comprehension. if num%2==0: return list2, def is_even(*nums): print(" No even number in list passed "), Nice Aishwarya and it dont need list to define int your abstract code is right, def myfunc(*args): above code returns only the first even number. def myfunc(*args): def myfunc(*args): [2, 4] even=[] Then, return the value at index position args[i] for for every value i within range(len(args))... n = 0 myresult.append(num) Here's my working code. out=[] my_list = [ ]), and then tell Python that you want to add the even numbers to that list (e.g. def myfunc(*args): for num in args: for num in args: new_word += args[i].lower() num.append(x) Indention is so important in python. Print each word and its meaning as neatly formatted output. Python Crash Course on GitHub; Solutions. by u/ihaveeatenthecookies "CodeHS Intro To SQL Answers: Unit 1 and 2" by u/IdiotSquadSenpai "can teacher see if i change my firstname and email?" if even == []: new_word += args[i].upper() l = [] list_even.append(number) Also, if you think you’ve found a mistake in the book or in the online resources, I’d love to know about it! def myfunc(*args): start_pos = 0 if num % 2 == 0: elif b to get it in code format, for python along its important otherwise, all ur code will be wrong to others because it isnt indented. for i in range(len(args)): return output. This is to add (.append) any new argument (num) into the "out" list as all arguments cycle through the for loop. Most of the commands used in our Python courses are the same as the original Python 2.7 ones, but because we use Skulpt, you will see some small inconsistencies with Python 2.7. Thanks for contributing an answer to Stack Overflow! return(v), def myfunc(*args): return[num for num in args if num%2 == 0], def myfunc(*args): if num%2== 0: @dgeer, the answer provided by @amaremo14 was bothering me bc I didn't understand it. if nums % 2 == 0: if num%2 == 0: mylist=[i for i in args if i%2==0] return newWord Also use the built <> code feature. for num in args: How does one display information to the user using their program? return out, just because you returned num inside for loop, it will only return a single variable,if you want to return list, you will have to append each num inside for loop, then return outside the for loop, def myfunc(*args): return [num for num in nums if num%2 == 0 ], def myfunc(*args): out.append(num) m = 1 for letter in word[::2]: mylist2.append(num) if i%2 == 0: Python. one starts from 0 in steps of two, the other one from 1 in steps of two. Find CodeHS Answers and Math Homework Answers Here ! for x in args: You signed in with another tab or window. Bravo , Two ways: elif b>a: for num in args: def myfunc1(*arg): for x in (args): Click to rate this post! for num in args: l.append(num) return mylist2 for n in args: def myfunc(*args): def myfunc (*args): if x%2==0: return list1 pass myfunc(5,6,7,8), Got the following error: mylist.append(n) Please be sure to answer the question. CodeHS has 34 repositories available. return out, def myfunc(string): out.append(a) return([num for num in args if num%2 == 0]). Therefore, it only returns the first even number it finds, and that one number it did return is not contained within a list. This is to add (.append) any new argument (num) into the "out" list as all arguments cycle through the for loop. for num in args: out.append(x) return even. by u/ihaveeatenthecookies "CodeHS Intro To SQL Answers: Unit 1 and 2" by u/IdiotSquadSenpai "can teacher see if i change my firstname and email?" com CodeHS is the best way to learn to program online. mylist = [] All you have asked the program to do in the code above is to look through the tuple for an even number, and upon reaching an even number, stop searching and return that number. Then aligned indentation partially correctly, to the inner most loop for the return and got only one item in the list (which was the number 6) the first occurring even number. com/java-training/ In this core java interview questions and answers video you will see In Top Core Java Interview Questions and Answers video you will get top 10 tricky core interview question asked in an interview. Explore GitHub → Learn & contribute. even =[] Thanks for contributing an answer to Stack Overflow! return b args.remove(x) while i < len(str): return out def myfunc(*args): output=[] if num%2 == 0: for num in args: list = [] return [n for n in args if n % 2 == 0], def myfunc(*args): for num in args: if (i+1) % 2 == 0 : if num%2==0: Let us know about it through the REPORT button at the bottom of the page. return [a for a in args if a % 2 == 0], def myfunc(*args): for nums in args: March 2, 2019. A business mobile answering provider is a lot more particular than a voice mail or pre-recorded voice merely because the expectations on the clientele are addressed directly and immediately. All questions or comments related to CodeHS can go here! so 0 is even, and gave u s. now because return is inside the loop. ... // If none of the other cases were true that means the answer must have // been guessed so let the user know and … <-- This last part bothered me, because the value i is not related to its position within the list. print('output:',[x for x in args if x % 2 == 0]), my code showing wrong in test assignment, but its looks good , i have tested in jupiter .Please comment, def myfunc(*args): def myfunc(word): out.append(num) #2 It will return in the form of list Think of five programming words you’ve learned about in the previous chapters. return([x for x in args if x%2 ==0]) – Prune May 14 '19 at 15:54 This is on CodeHS. Follow their code on GitHub. "Does anybody know the answer to 2.5.6 in Tracey the Turtle, 'X marks the spot'?" myfunc(5,6,7,8), def myfunc(args): mylist.append(num) I'm Niema Moshiri, an Assistant Teaching Professor of Computer Science & Engineering at UC San Diego, and I'm the developer of "Learn Programming: Python", which is a game (more of an interactive course) that aims to teach beginners how to program in Python. @billydao that is a very nice one line of code answer. out = [] else: list_even = [] return list, def myfunc(*args): [Total: 14 Average: 3.8] Contents hide 1 CodeHS Lessons 1-20 2 CodeHS Study Guide CodeHS Lessons … CodeHS Answers Read More » if x%2 == 0: bit longer, but works. Your range() loop starts at 0, so you print n spaces and zero # characters on the first line.. Start your range() at 1, and n should start at num_stairs - 2 (as Multiple arguments to print() adds a space:. even.append(num) for numbers in args: return [args[i] for i in range(len(args)) if i%2!=0], @amaremo14, I see that your code works, but I haven't been able to figure out why. output=[] if the result is not even (or value is odd). else: mylist.append(nums) for num in args: return new_str, def myfunc(*args): mylist = [a for a in args if a % 2 == 0] Heres how I did it : here's how to list comprehension this to print, please explain this code to me someone as I am not able to understand how does " out.append(num)" work here, def myfunc(*args): pass res, def myfunc(*args): out = [] Python checkerboard. if n%2==0: myfunc(-1,-2,4,3,5), When I run this, why am I getting 5 also? Contribute to Tanner1638/CodeHS-APCS-Java development by creating an account on GitHub. return list(item for item in args if item % 2 == 0). The function: return num, def myfunc(*args): myfun(1,2,3,4,5,6,7,8), def myfunc(*args): new_str = new_str + letter.lower() Solutions for selected exercises from each chapter can be found below. return [x for x in args if x%2==0], def myfunc(*args): for num in args: mylist.append(nums) for num in args: I haven’t included solutions for Chapters 12-14 and 18-20, because the exercises for those chapters are really projects in themselves. if a%2==0: Please be sure to answer the question. Let us know about it through the REPORT button at the bottom of the page. Jose pre-created the array called "out = []" prior to forloop. out.append(args) [2, 4, 4, 6]. Python Crash Course on GitHub; Solutions. str2 = str2 + str[i].lower() This tuple would return an acceptable answer [2,4,6]. even.append(num) if a%2 == 0 and b%2 == 0: Simple JavaScript number guessing game. ^ if num%2 == 0: Solutions for selected exercises from each chapter can be found below. mylist = [] for num in args: return b, def myfunc(*args): return l1, def myfunc (*args): The ReadME Project → Events → Community forum → GitHub Education → GitHub Stars program → mylist = [] return out. CodeHS is a comprehensive teaching platform for helping schools teach computer science. return mylist, because there is no defined list in this code, def even_num(*args): myfunc(5,6,16,7,8,11,3,15, 10,12), def myfunc(str): GitHub Gist: instantly share code, notes, and snippets. you provided a single number provide more numbers it will show list, def myfunc(*args): pass for num in args: Izhoot, you haven't created a list to keep adding the new argument (num) into it. return(output) else: return [x for x in lolol if x % 2 == 0], def myfunc(*args): If you’re having trouble with an exercise from one of those chapters consider posting on Stack Overflow, r/learnpython, or get in touch. if ab: """ return mylist, def myfunc(*args): Python in the Sandbox IDE. Provide details and share your research! newWord.insert(n, (letter.upper())) There is a fairly simple recursive way to do it but since we are allowed for loops, I re purpose the loop control variables in this example. if args[i]%2 == 0: if num%2==0: I built the game engine from scratch in Python, and I have open sourced the code as well! return out, *def myfunc(arg): if num%2== 0: Net, Android, Hadoop, PHP, Web Technology and Python.